-2h^2+8h-7=0

Solution for -2h^2+8h-7=0 equation:

-2h^2+8h-7=0

a = -2; b = 8; c = -7;
Δ = b2-4ac
Δ = 82-4·(-2)·(-7)
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{2}}{2*-2}=\frac{-8-2\sqrt{2}}{-4}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{2}}{2*-2}=\frac{-8+2\sqrt{2}}{-4}
$